A) I
B) II
C) III
D) IV
Correct Answer
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Multiple Choice
A) 1
B) 2
C) 3
D) 4
Correct Answer
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Multiple Choice
A) 1
B) 2
C) 3
D) 4
Correct Answer
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Multiple Choice
A) I < II < III < IV
B) II < I < III < IV
C) I < II < IV < III
D) IV < III < II < I
Correct Answer
verified
Multiple Choice
A) The rate-determining step in bromination is exothermic.
B) Both radicals are formed.
C) A mixture of products results.
D) A single radical halogenation product predominates.
Correct Answer
verified
Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
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Multiple Choice
A) Carbon radicals are classified as primary,secondary,tertiary,or quaternary.
B) A carbon radical is sp2 hybridized.
C) The geometry of a carbon radical is trigonal planar.
D) The unhybridized p orbital in a carbon radical contains the unpaired electron.
Correct Answer
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Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
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Multiple Choice
A) Bromination is unselective,yielding a mixture of products.
B) Chlorination is often selective,yielding one major product.
C) Chlorination is faster than bromination.
D) Bromination is faster than chlorination.
Correct Answer
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Multiple Choice
A) The rate-determining step in chlorination is endothermic.
B) The transition state resembles the product.
C) The more stable radical is formed faster.
D) A mixture of products results.
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Multiple Choice
A) O3
B) O2
C) Vitamin C
D) CO2
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Multiple Choice
A) Cyclic bromonium ion
B) Allylic carbocation
C) Allylic carbanion
D) Allylic radical
Correct Answer
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Multiple Choice
A) 1
B) 2
C) 3
D) 4
Correct Answer
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Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
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Multiple Choice
A) 1,2,3
B) 1,3,2
C) 2,3,1
D) 3,2,1
Correct Answer
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Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
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Multiple Choice
A) Most radicals are unstable.
B) A radical contains an atom that has an octet of electrons.
C) Half-headed arrows are used to show the movement of lone electrons.
D) A radical is formed by homolysis of a covalent bond.
Correct Answer
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Multiple Choice
A) Only I
B) Only II
C) Only III
D) Only I and II
Correct Answer
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Multiple Choice
A) Light or heat provides the energy needed for homolytic bond cleavage to form radicals.
B) Breaking the weak O-O bond of peroxides initiates radical reactions.
C) The diradical O2 removes radicals from a reaction mixture.
D) Radicals rearrange.
Correct Answer
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Multiple Choice
A) II > IV > III > I
B) III > II > IV > I
C) IV > III > II > I
D) IV > III > I > II
Correct Answer
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